(27x^2-24x+10)/(9x-8)

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Solution for (27x^2-24x+10)/(9x-8) equation: 


D( x )

9*x-8 = 0

9*x-8 = 0

9*x-8 = 0

9*x-8 = 0 // + 8

9*x = 8 // : 9

x = 8/9

x in (-oo:8/9) U (8/9:+oo)

(27*x^2-(24*x)+10)/(9*x-8) = 0

(27*x^2-24*x+10)/(9*x-8) = 0

27*x^2-24*x+10 = 0

27*x^2-24*x+10 = 0

DELTA = (-24)^2-(4*10*27)

DELTA = -504

DELTA < 0

1 = 0

1/(9*x-8) = 0

x belongs to the empty set

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